racket - How to convert a list into xexpr? -

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#lang racket (struct result (q) #:mutable)  (define result (result '()))  (define (insert-result! result val)   (set-result-q! result (cons val (result-q result))))  (insert-result! result "hello") (insert-result! result "wrold") (print (result-q result))  (define (iter l) `(div ((class "result"))     ,(for ([i (result-q l)])       `(p ,i))))  (iter result)

i'm trying xexpr. result should '("wrold" "hello") after code run. in iter function want produce output:

'(div ((class "result")) (p "world") (p "hello"))

somehow code above gives me '(div ((class "result")) #<void>) instead. how fix issue?

you should use:

,@(for/list ([i (result-q l)])     `(p ,i))

notice use of ,@ splicing unquote, for/list collecting results list.


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