python - Having trouble using "in" function to check for containment of one array in another -

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the current code extremely short. if understand "in" function correctly, shouldn't loop iterate , return true if both [1,3] in [1,4,5]? right getting true of tests. feel there easy fix this, don't know.

i tried putting if statement in-between , return lines still returned true.

def innerouter(arr1, arr2):     arr1 in arr2:          return true      return false

you have use if one_element in array

def innerouter(arr1, arr2):     x in arr1:         if x not in arr2:             return false     return true  innerouter([1,3], [1,4,5]) # false innerouter([1,4], [1,4,5]) # true

or can use set() check 

def innerouter(arr1, arr2):     return set(arr1).issubset(set(arr2))  innerouter([1,3], [1,4,5]) # false innerouter([1,4], [1,4,5]) # true

the same:

def innerouter(arr1, arr2):     return set(arr1) <= set(arr2)

https://docs.python.org/2/library/sets.html#set-objects


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