algorithm - How can I iterate through a two-dimensional array in a snail mode, with a single cycle? -

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given two dimensional array, iterate through in snail mode , print out elements using one single cycle.

for example if given array is:

10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34

the program should print out:

10 15 20 25 30 31 32 33 34 29 24 19 14 13 12 11 16 21 26 27 28 23 18 17 22

so starting upper-left corner , arriving center of array.

here solution 1 loop:

it works when matrix is: n >= m 

#include <iostream>  using namespace std;  int main() { //    int arr[4][3] = {{0, 9, 8} , {1, 10 , 7} , {2, 11, 6} , {3, 4, 5}}; //    int n = 4, m = 3;      int arr[4][4] = {{0, 11, 10, 9} , {1, 12, 15, 8} , {2, 13, 14, 7} , {3, 4, 5, 6}};     int n = 4, m = 4;      int row = 0, col = 0, turn = 0;     bool istop = true;      for(int nrelem = 0; nrelem <= (n*m); nrelem++)     {         //this part make left, bottom, right part ( u form )         if((row < n-1-turn) && (col != m-1) && (istop == true))         {             cout << " " << arr[row][col];             row++;         } else {             if((row == n-1-turn) && (col < m-1-turn))             {                 cout << " " << arr[row][col];                 col++;             } else {                 if((col == m-1-turn) && (row > 0))                 {                     cout << " " << arr[row][col];                     row--;                 } else {                     istop = false;                 }             }         }         //          //and top backward parsing         if((col > 0) && (istop == false))         {             cout << " " << arr[row][col];             col--;         } else {             if (istop == false)             {                 istop = true;                 turn++;                 row += turn;                 col += turn;             }         }     }      cout << endl;     return 0; }

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