assembly - Assembler i8080 Multiplying two 16bits numbers -

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i have prepare program i8080 processor. program have multiplying 2 16b numbers. don't know how check multiplier bit bit.

e.g 1111 * 1011 = first bit of 1011 1 add 1111 second bit 1 add 11110 third bit 0 don't add 111100 forth 1 add 1111000

result 1111+11110+1111000=10100101

and problem how chceck bits of multiplier?

thanks help

probably easiest way shift right , check carry, otherwise have keep changing bit test , that's hard, register pair. shifting bit annoying on 8080 since a can rotated. let's multiplier in bc (and multiplicand in hl , result in de can shift multiplicand dad h , takes xchg add-to-result happens less often)

mov a, b ora    ; reset carry rar mov b, mov a, c rar mov c, jnc skipadd

using ora a ensures multiplier goes zero, allows exit test such as:

mov a, b ora c jnz looptop

if unroll 16 can fill bc left carry left shift of multiplicand, won't make difference.


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