PHP ERROR : mysqli_stmt_bind_param() Number of variables doesn't match number of parameters in prepared statement -

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i facing problem in php file, error comming parameters in third statement, can not find it. here php file:

$client = "test"; $resto = "test";  $st1 = mysqli_query($con, "select client_id clients email = '$client'"); $res1 = mysqli_fetch_array($st1); $clientid = $res1["client_id"];  echo "client id = "; echo $clientid;  $st2 = mysqli_query($con, "select restaurant_id restaurants email = '$resto'"); $res2 = mysqli_fetch_array($st2); $restaurantid = $res2["restaurant_id"];  echo "resto id = "; echo $restaurantid;  $statement = mysqli_prepare($con, "insert reservations (resto_id, client_id) values ($restaurantid,$clientid)");  mysqli_stmt_bind_param($statement,"ii",$restaurantid,$clientid); mysqli_stmt_execute($statement);  $response = array(); $response["success"] = true;    echo json_encode($response);

thank in advance help.

change statement bellow 

$statement = mysqli_prepare($con, "insert reservations (resto_id, client_id) values ( ? , ? )");

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