linux - How to get only ip addresses from the echo stat command -
when executing below command
echo stat | nc localhost 2181
i getting
zookeeper version: 3.4.6-1569965, built on 02/20/2014 09:09 gmt clients: /10.999.87.01:56046[1](queued=0,recved=95261,sent=95261) /10.888.98.02:47356[1](queued=0,recved=45856,sent=45856) /10.777.09.03:53636[1](queued=0,recved=96378,sent=96380) latency min/avg/max: 0/0/316 received: 3034250 sent: 3035252 connections: 3 outstanding: 0 zxid: 0x21000351cf mode: follower node count: 2740
can me separate ip addresses below using commands
10.999.87.01 10.888.98.02 10.777.09.03
so question have commands this. if yes please help. :)
... nc .... | awk -f: '/^[\/]/{sub(/^[\/]/,"",$1);print $1}'
output
10.999.87.01 10.888.98.02 10.777.09.03
Comments
Post a Comment