awk match() multiple matches -

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i have following:

echo as:i:0  uq:i:0  zz:z:mus.sup  nm:i:0  md:z:50  zz:z:cas.sup  co:z:endofline|awk '{match($0,/zz:z[^ ]*/,m); print m[0], m[1]}'

which unfortunately outputs first entry (out of two): 

zz:z:mus.sup

it looks me match() function incapable of storing more 1 match array. unless i'm missing here something...?

if indeed case, kindly suggest awk-based 'matching' alternative allow obtain 2 zz:z entries. note, these not located each time @ same column(!) - hence need of using match() function.

the general idea here obtain @ same awk command values appear @ known column positions (e.g. col1, col2), , values (fetched based on unique signature "zz:z") located @ unknown indexed columns.

in addition, following attempt - using gensub() fails output/print 2 zz:z entries, , identify 1 of 2 (and other 1 upon deprecation of reciprocal..)

echo as:i:0  uq:i:0  zz:z:mus.sup  nm:i:0  md:z:50  zz:z:cas.sup  co:z:endofline|awk '{val= gensub(/.*(zz:z[^ ]*).*/,"\\1 \\2","g",$0);print val}'

the result in case is:

zz:z:cas.sup

but i'd have result:

zz:z:mus.sup zz:z:cas.sup

you calling wrong function, should using split() not match():

$ echo as:i:0  uq:i:0  zz:z:mus.sup  nm:i:0  md:z:50  zz:z:cas.sup  co:z:endofline| awk '{split($0,t,/zz:z[^ ]*/,m); print m[1], m[2]}' zz:z:mus.sup zz:z:cas.sup

or print number of occurrences in order appeared in input:

$ echo as:i:0  uq:i:0  zz:z:mus.sup  nm:i:0  md:z:50  zz:z:cas.sup  co:z:endofline| awk '{split($0,t,/zz:z[^ ]*/,m); (i=1; in m; i++) print m[i]}' zz:z:mus.sup zz:z:cas.sup

that uses gnu awk 4th arg split() using gnu awk 3rd arg match().

if had in non-gnu awk it'd be:

$ echo as:i:0  uq:i:0  zz:z:mus.sup  nm:i:0  md:z:50  zz:z:cas.sup  co:z:endofline| awk '{while(match($0,/zz:z[^ ]*/)) {print substr($0,rstart,rlength); $0=substr($0,rstart+rlength)}}' zz:z:mus.sup zz:z:cas.sup

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