Sorting for index values using a binary search function in python -

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i being tasked designing python function returns index of given item inside given list. called binary_sort(l, item) l list(unsorted or sorted), , item item you're looking index of.

here's have far, can handle sorted lists

def binary_search(l, item, issorted=false):  templist = list(l) templist.sort()  if l == templist:     issorted = true  = 0 j = len(l)-1  if item in l:      while != j + 1:         m = (i + j)//2         if l[m] < item:             = m + 1          else:             j = m - 1      if 0 <= < len(l) , l[i] == item:         return(i) else:     return(none)

how can modify return index of value in unsorted list if given unsorted list , value parameters?

binary search (you misnamed - algorithm above not called "binary sort") - requires ordered sequences work.

it can't work on unordered sequence, since ordering allows throw away @ least half of items in each search step.

on other hand, since allowed use list.sorted method, seems way go: calling l.sort() sort target list before starting search operations, , algorithm work.

in side note, avoid in program call l - maybe nice name list background in mathematics , used things on paper - on screen, l hard disinguish 1 , makes poor source code reading. names case sequence lst, or data. (list should avoided well, since override python built-in same name).


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