javascript - Get object that was destructured in parameter -

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• es6 destructuring function parameter - naming root object 2 answers

suppose have function takes destructured object parameter in arrow function:

const myfunc = ({a, b, c}) => { }; 

is there anyway or syntax allow me whole object single value well? since arrow function doesn't bind arguments, can't use that.

is possible name it, along lines of:

const myfunc = (allargs: {a, b, c}) => {     console.log(allargs); }; myfunc({a:1, b:2, c:3}); // output: {a:0, b:1, c: 2} 

obviously, isn't deal breaker , there plenty of workarounds (either don't use arrow function, don't destructure, or recreate object when need it), i'd know convenience sake.

you destructure single param quite easily. lose advantage of terse destructuring syntax in arguments, it's easy , still clear:

const myfunc = (allargs) => {     const {a, b, c} = allargs;     console.log(allargs); }; 

alternatively, consider whether need arrow function. if don't need access lexical this perhaps old-fashioned function() {} trick , give access arguments.